Science
posted by Khumalo Lindokuhle on .
A long jumper leaves the ground at an angle of 20 degrees above horizontal and at a speed of 11m/s..how far does he jump?

time in air:
hf=ho+vo*sin20*t4.9t^2
hf,ho=0, vo given 11m/s solve for time.
Now, how far
d=voCos20*time