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A long jumper leaves the ground at an angle of 20 degrees above horizontal and at a speed of 11m/s..how far does he jump?

  • Science - ,

    time in air:

    hf=ho+vo*sin20*t-4.9t^2
    hf,ho=0, vo given 11m/s solve for time.
    Now, how far
    d=voCos20*time

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