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March 27, 2015

March 27, 2015

Posted by **tabeershah** on Saturday, March 1, 2014 at 12:57am.

- math -
**Steve**, Saturday, March 1, 2014 at 5:46amif the front of the log is x feet from the bridge, and y is the length of the log, then

30/x = tan 16.7°

30/(x+y) = tan 14°

eliminate x:

30/tan 16.7° = 30/tan 14° - y

Now solve for y:

y = 30(cot 14° - cot 16.7°)

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