Posted by **Gregory** on Friday, February 28, 2014 at 11:56pm.

Find the domain:

a) [sqrt(x+3)]+[5x^2-180]

b) [sqrt(x+3)]/[5x^2-180]

c) (8x+9)(9x+8)

d) (8x+9)/(9x+8)

e) [sqrt(x+2)](5x^2-245)

f) [sqrt(x+2)]/(5x^2-245)

- Algebra - Functions -
**Steve**, Saturday, March 1, 2014 at 5:58am
all polynomials have domain of (-∞,+∞)

√u has domain u >= 0

rational functions have domains which exclude where the denominator is zero.

Keeping that in mind, I'll do (b), and the rest should be easy.

√(x+3) needs x+3 >= 0, or x >= -3

the domain also excludes x=±6, since then 5x^2-180=0, and you cannot divide by zero. -6 is already excluded by the √, so the domain is [-3,6)∪(6,∞)

## Answer this Question

## Related Questions

- Math Help please!! - Could someone show me how to solve these problems step by ...
- math,algebra,help - Directions are simplify by combining like terms. x radiacal ...
- Math - How do you find a square root of a number that's not a perfect square? I'...
- Mathematics - sqrt 6 * sqrt 8 also sqrt 7 * sqrt 5 6.92820323 and 5.916079783 So...
- Math(Roots) - sqrt(24) *I don't really get this stuff.Can somebody please help ...
- Inequality - When I solve the inquality 2x^2 - 6 < 0, I get x < + or - ...
- math-Inverse functions - f(x)=-4x-2 & g(x)=5x-6. Find (f*g) and state domain. f(...
- math calculus please help! - l = lim as x approaches 0 of x/(the square root of...
- Math/Calculus - Solve the initial-value problem. Am I using the wrong value for ...
- Calculus - Please look at my work below: Solve the initial-value problem. y'' + ...