Friday

August 1, 2014

August 1, 2014

Posted by **Alexis** on Friday, February 28, 2014 at 8:49pm.

- Pre-Calculus -
**Reiny**, Friday, February 28, 2014 at 9:19pmwe know x =rcosØ and y = rsinØ

-3rcosØ + (1/2)rsinØ = 2

-6rcosØ + rsinØ = 2

r(sinØ - 6cosØ) = 2

or

r = 2/(sinØ - 6cosØ)

looks good:

http://www.wolframalpha.com/input/?i=polar+r+%3D+2%2F%28sinx+-+6cosx%29

- Pre-Calculus -
**Steve**, Saturday, March 1, 2014 at 6:20amReiny gave you good polar coordinates, but if all you want is parametric equations, try

x = t/3

y = 1 + t/2

or

x = -(2+t)/3

y = -2t

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