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March 1, 2015

March 1, 2015

Posted by **Alexis** on Friday, February 28, 2014 at 8:49pm.

- Pre-Calculus -
**Reiny**, Friday, February 28, 2014 at 9:19pmwe know x =rcosŲ and y = rsinŲ

-3rcosŲ + (1/2)rsinŲ = 2

-6rcosŲ + rsinŲ = 2

r(sinŲ - 6cosŲ) = 2

or

r = 2/(sinŲ - 6cosŲ)

looks good:

http://www.wolframalpha.com/input/?i=polar+r+%3D+2%2F%28sinx+-+6cosx%29

- Pre-Calculus -
**Steve**, Saturday, March 1, 2014 at 6:20amReiny gave you good polar coordinates, but if all you want is parametric equations, try

x = t/3

y = 1 + t/2

or

x = -(2+t)/3

y = -2t

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