Find the distance between A and B.

A= the coordinates ( 6, 1)

B= the coordinates ( 2, -3)

answer choices are:
A. 8 units
B. 16 units
C. 2 times the square root of 2 units
D. 4 times the square root of 2 units

the distance is the length of the hypotenuse of the right triangle whose legs are 4 and 4

Looks like (D)

-3 - 1 = -4

2 - 6 = -4
sqrt [(-4)^2 + (-4)^2] = sqrt (2*16)
= 4 sqrt 2

HOW DO YOU GET THAT AS A ANSWER PLEASE? :)

thank u guys so much!! <3

To find the distance between two points A and B in a coordinate plane, we can use the distance formula. The distance formula is derived from the Pythagorean theorem and it calculates the length of the straight line segment connecting two points in a plane.

The distance formula is given by:

Distance = sqrt((x2 - x1)^2 + (y2 - y1)^2)

Let's substitute the given coordinates into the formula.

x1 = 6, y1 = 1 (coordinates of point A)
x2 = 2, y2 = -3 (coordinates of point B)

Distance = sqrt((2 - 6)^2 + (-3 - 1)^2)
Distance = sqrt((-4)^2 + (-4)^2)
Distance = sqrt(16 + 16)
Distance = sqrt(32)

Now, simplify the square root value:

Distance = sqrt(16 * 2)
Distance = sqrt(2 * 8)
Distance = sqrt(2) * sqrt(4^2)
Distance = 4 * sqrt(2)

Therefore, the distance between point A and point B is 4 times the square root of 2 units. Hence, the correct answer choice would be option D - 4 times the square root of 2 units.