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July 28, 2014

July 28, 2014

Posted by **Anonymous** on Friday, February 28, 2014 at 3:45pm.

At what speed does the wreckage move if one car was driving north and one east?

- Physics -
**Damon**, Friday, February 28, 2014 at 4:30pmbefore

x momentum = 17,000 (east)

y momentum = 17,000 (north)

after

m Vx = 2000 V cos T = 17,000 still

m Vy = 2000 V sin T = 17,000 still

so

sin T = cos T so T = 45 deg and sin = cos =sqrt2 /2

2000 V (sqrt 2/2) = 17,000

V = 17 /sqrt 2 = 12 m/s

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