the smallest regulation golf ball has a volume of 2.48 cubic inches. if the diameter of the ball were increased by 10%, or a factor of 1.1, what will the volume of the golf ball be?

(4/3) pi R^3

(4/3) pi (1.1 R)^3

so
ratio = 1.1 ^3 = 1.331

1.331 * 2.48 = 3.3 in^3

To find the volume of the golf ball after increasing the diameter by 10%, you can use the formula for the volume of a sphere:

V = (4/3) * π * r^3,

where V represents the volume and r represents the radius of the sphere. Since we are given the volume, which is 2.48 cubic inches, we need to solve for the radius.

First, we need to find the radius of the original golf ball. The regulation size for a golf ball is a diameter of 1.68 inches, which means the radius is half of that:

r = 1.68 / 2 = 0.84 inches.

Now, to find the new volume after increasing the diameter by 10%, we need to calculate the new radius. The new radius is 1.1 times the original radius:

new_radius = 1.1 * 0.84 = 0.924 inches.

Plugging this new radius value into the volume formula:

V = (4/3) * π * (0.924)^3.

Calculating:

V ≈ 2.909 cubic inches.

Therefore, the volume of the golf ball after increasing the diameter by 10% would be approximately 2.909 cubic inches.