what volume would 4.3 moles of hydrogen gas occupy at 45 degrees and 3.22 atm?
Use PV = nRT
To find the volume of gas, we can use the ideal gas law equation:
PV = nRT
Where:
P = Pressure (in atmospheres)
V = Volume (in liters)
n = Number of moles
R = Ideal Gas Constant (0.0821 L.atm/mol.K)
T = Temperature (in Kelvin)
First, we need to convert the given temperature from degrees Celsius to Kelvin:
T(K) = T(°C) + 273.15
T(K) = 45°C + 273.15 = 318.15 K
Now, we can substitute the given values into the ideal gas law equation:
(3.22 atm) * V = (4.3 moles) * (0.0821 L.atm/mol.K) * (318.15 K)
Multiply the moles by the ideal gas constant and temperature:
(3.22 atm) * V = 112.205 L.atm
Finally, solve for V by dividing both sides of the equation by 3.22 atm:
V = 112.205 L.atm / 3.22 atm
V ≈ 34.82 liters
Therefore, 4.3 moles of hydrogen gas at 45 degrees Celsius and 3.22 atm pressure would occupy approximately 34.82 liters of volume.