Find the mass of 0°C ice that 10g of 100 °C steam will completely melt
To calculate the mass of ice that will be completely melted by a given amount of steam, we need to consider the heat transfer that occurs during the phase change from steam to ice.
The process involved here is called the heat transfer equation, which states that:
Q = m * L
Where:
Q is the amount of heat transferred
m is the mass of the substance
L is the specific latent heat of the substance
In this case, we need to find the mass of ice, so we rearrange the equation to solve for m:
m = Q / L
Given:
Q = 10g (mass of steam)
L = specific latent heat of ice
The specific latent heat of ice is the amount of heat required to change one gram of ice at 0°C to water at 0°C. It is commonly known as the latent heat of fusion. For ice, the value is approximately 334 J/g.
Substituting the given values into the formula:
m = 10g / 334 J/g
Calculating this, we get:
m ≈ 0.03 g
Therefore, approximately 0.03 grams of ice at 0°C will be completely melted by 10 grams of steam at 100°C.