5.00 mL of 2.00x10^-3M Fe(NO3)3 is mixed with 4.03 mL of 2.00x10^-3M NaSCN and 1.08 mL of 0.1M HNO3, for a total volume of 10.11 mL.

a) What is the initial concentration of the Fe(NO3)3 in the mixed solution?
b) What is the initial concentration of the NaSCN in the moxed solution?

a. 2.00E-3 x (5.00/total volume) = ?

b. 2.00E-3 x (4.03/total volume) = ?

To find the initial concentration of Fe(NO3)3 in the mixed solution, we need to use the following formula:

C1V1 = C2V2

Where:
C1 = initial concentration of Fe(NO3)3
V1 = initial volume of Fe(NO3)3
C2 = final concentration of Fe(NO3)3 (which is the concentration of the mixed solution)
V2 = final volume of the mixed solution

Given:
C2 = 2.00x10^-3 M (concentration of the mixed solution)
V2 = 10.11 mL (volume of the mixed solution)
V1 = 5.00 mL (volume of Fe(NO3)3 solution)

Substituting the given values into the formula, we can solve for C1:

C1(5.00 mL) = (2.00x10^-3 M)(10.11 mL)

C1 = (2.00x10^-3 M)(10.11 mL) / 5.00 mL

C1 ≈ 4.04x10^-3 M

So, the initial concentration of Fe(NO3)3 in the mixed solution is approximately 4.04x10^-3 M.

To find the initial concentration of NaSCN in the mixed solution, we can use the same formula:

C1V1 = C2V2

Where:
C1 = initial concentration of NaSCN
V1 = initial volume of NaSCN
C2 = final concentration of NaSCN (which is the concentration of the mixed solution)
V2 = final volume of the mixed solution

Given:
C2 = 2.00x10^-3 M (concentration of the mixed solution)
V2 = 10.11 mL (volume of the mixed solution)
V1 = 4.03 mL (volume of NaSCN solution)

Substituting the given values into the formula, we can solve for C1:

C1(4.03 mL) = (2.00x10^-3 M)(10.11 mL)

C1 = (2.00x10^-3 M)(10.11 mL) / 4.03 mL

C1 ≈ 5.02x10^-3 M

So, the initial concentration of NaSCN in the mixed solution is approximately 5.02x10^-3 M.