A small plane flying a banner in the shape of a rectangle the area of the banner is hundred and 44 square the width of the banner is one fourth the length of the banner what are the dimensions of the banner

L * L/4 = 144 ???

L^2 = 4*144
then
L = 2 * 12
L = 24
(1/4) L = 6

24

To find the dimensions of the banner, we can use the given information about the area and the relationship between the width and length.

Let's assume the length of the banner is x.

According to the problem, the width of the banner is one-fourth the length. So, the width can be represented as (1/4)x.

To find the area of a rectangle, we multiply its length by its width. We are given that the area of the banner is 144 square units, so we can write the equation:

Length × Width = Area
x × (1/4)x = 144

Simplifying the equation, we have:
(x^2) / 4 = 144

To solve for x, we can multiply both sides of the equation by 4 to eliminate the denominator:
x^2 = 144 × 4
x^2 = 576

Taking the square root of both sides, we get:
x = √576
x = 24

Thus, the length of the banner is 24 units.

To find the width, we can substitute the value of the length (24) into the equation for the width:
Width = (1/4) × length
Width = (1/4) × 24
Width = 6

Therefore, the dimensions of the banner are 24 by 6 units.