An aqueous solution is analyzed and found to contain potassium ions and sulfite ions. Write the equation for the dissolution of the salt that produced this solution. If the solution contains 0.600 mol of potassium ions, how many moles of sulfite ions are present? Answer in units of mol

See your other posts under other screen names.

To write the equation for the dissolution of the salt, we need to determine the chemical formula of the salt. Given that the solution contains both potassium ions (K+) and sulfite ions (SO3^2-), the chemical formula of the salt can be determined by finding the lowest whole number ratio of the ions.

The chemical formula of the salt is K2SO3. This means that two potassium ions are combined with one sulfite ion to form the salt.

Now, according to the given information, the solution contains 0.600 mol of potassium ions (K+). Since the chemical formula of the salt is K2SO3, we can determine the number of moles of sulfite ions (SO3^2-) present by using the mole ratio between potassium ions and sulfite ions.

In the chemical formula K2SO3, there are two potassium ions (K+) for every one sulfite ion (SO3^2-). Therefore, for every two moles of potassium ions, there is one mole of sulfite ions.

Given that the solution contains 0.600 mol of potassium ions, we can calculate the number of moles of sulfite ions:

Number of moles of sulfite ions = (0.600 mol K+) / 2

Number of moles of sulfite ions = 0.300 mol

Therefore, there are 0.300 moles of sulfite ions present in the solution.