A -kg block is initially at rest on a frictionless horizontal surface. It is pulled with a constant horizontal force N. How long must it be pulled before its speed is m/s?
t pull =
To find the time it takes for the block to reach a certain speed, we can use Newton's second law and the kinematic equation for linear motion.
1. Start with Newton's second law:
F = ma
2. Rearrange the equation to solve for acceleration:
a = F / m
3. Since the block is initially at rest, its initial velocity is 0 m/s. We can use the kinematic equation to relate velocity, acceleration, and time:
v = at
4. Rearrange the equation to solve for time:
t = v / a
5. Substitute the given values into the equation:
t = m / (F / m)
Simplifying further:
t = m^2 / F
Therefore, the time it takes for the block to reach a speed of m/s is m^2 / F seconds.