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December 21, 2014

December 21, 2014

Posted by **Abby** on Friday, February 21, 2014 at 4:55pm.

(3/2b^4)^3

(3/5y^4)^-2

- Math! HELP! -
**Abby**, Friday, February 21, 2014 at 4:58pmReiny, Steve!! I need help!

- Math! HELP! -
**Reiny**, Friday, February 21, 2014 at 5:16pm(3/2b^4)^3

= (27/8)b^12

(3/5y^4)^-2

= 1/(3/5y^4)^2

= 1/( (9/25)y^8

= 25/(9y^8)

or

(25/9)y^-8

- Math! HELP! -
**Abby**, Friday, February 21, 2014 at 5:56pmCan you help me with some graph ones?

- Math! HELP! -
**Bosnian**, Friday, February 21, 2014 at 6:35pm[ ( 3 / 2 ) b ^ 4 ] ^ 3 =

[ ( 3 ^ 3 ) / ( 2 ^ 3 ) ] * ( b ^ 4 ) ^ 3 =

( 27 / 8 ) * b ^ ( 4 * 3 ) =

( 27 / 8 ) * b ^ 12 =

27 b ^ 12 / 8

( 3 / 5 y ^ 4 )^ ( - 2 ) =

[ ( 3 ^ ( - 2 ) ] / [ ( 5 ^ ( - 2 ) ] * [ y ^ 4 ^ ( - 2 ) ] =

( 1 / 3 ^ 2 ) / ( 1 / 5 ^ 2 ) * y ^ [ 4 * ( - 2 ) ] =

( 1 / 9 ) / ( 1 / 25 ) * ( y ^ - 8 ) =

[ ( 1 * 25 ) / ( 1 * 9 ) ] * 1 / y ^ 8 =

( 25 / 9 ) * 1 / y ^ 8 =

25 / 9 y ^ 8

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