A ball of mass m strikes a wall that is perpendicular to its path at speed +v and rebounds in the opposite direction with a speed –v. The impulse imparted to the ball by the wall is

1) 2mv 2)mv 3)-mv 4)zero 5)-2mv

The impulse imparted to the ball by the wall can be determined using the principle of conservation of momentum.

The momentum before the collision is given by the product of the mass (m) and the velocity (+v), which is mv. Since the ball rebounds in the opposite direction, the momentum after the collision is given by the product of the mass (m) and the velocity (-v), which is -mv.

The change in momentum is calculated by subtracting the initial momentum from the final momentum:

Change in momentum = Final momentum - Initial momentum = (-mv) - (mv) = -2mv

Therefore, the impulse imparted to the ball by the wall is -2mv.

So, the correct answer is 5) -2mv.

To find the impulse imparted to the ball by the wall, we can use the principle of impulse-momentum.

Impulse is defined as the change in momentum of an object. In this case, the momentum of the ball changes from +mv to -mv. The change in momentum is given by:

Change in momentum = final momentum - initial momentum
Change in momentum = (-mv) - (+mv)
Change in momentum = -2mv

Therefore, the impulse imparted to the ball by the wall is -2mv.

So the correct answer is option 5) -2mv.

sce bh