Posted by **Anonymous** on Friday, February 21, 2014 at 2:48pm.

Can someone simply tell me what methods I must use in order to solve this word problem? Please, don't include the answer. I wish to solve this on my own. However, I would truly appreciate it if anyone could evaluate my answer afterwards.

"A rectangle has a width w and its length is 4 units longer than 2 times the width, or 2w + 4. Write a polynomial for the area of the rectangle."

- Algebra 1 -
**Bosnian**, Friday, February 21, 2014 at 3:01pm
L = 2 W + 4

A = W * L

- Algebra 1 -
**Bosnian**, Friday, February 21, 2014 at 3:03pm
L = 2 W + 4

A = W * L

A = W * ( 2 W + 4 )

A = 2 W ^ 2 + 4 W

A = 2 ( W ^ 2 + 2 W )

- Algebra 1 -
**Anonymous**, Friday, February 21, 2014 at 3:05pm
Have you provided me with a method or the answer?

- Algebra 1 -
**Bosnian**, Friday, February 21, 2014 at 3:06pm
Both

- Algebra 1 -
**Anonymous**, Friday, February 21, 2014 at 3:08pm
Which is which?

- Algebra 1 -
**Bosnian**, Friday, February 21, 2014 at 3:10pm
Area of rectangle = width * length

- Algebra 1 -
**Anonymous**, Friday, February 21, 2014 at 3:10pm
So the answer is: A = 2w^2 + 4w?

- Algebra 1 -
**Bosnian**, Friday, February 21, 2014 at 3:11pm
A = W * L =

W * ( 2 W + 4 ) =

W * 2 W + W * 4 =

2 W ^ 2 + 4 W =

2 ( W ^ 2 + 4 W )

- Algebra 1 -
**Anonymous**, Friday, February 21, 2014 at 3:12pm
The answer is 2 ( W ^ 2 + 4 W )? I wouldn't simplify it?

- Algebra 1 -
**Bosnian**, Friday, February 21, 2014 at 3:16pm
A = 2 w ^ 2 + 4 w

OR

A = 2 ( w ^ 2 + 4 w )

OR

A = 2 w ( w + 4 )

All three is same answer.

- Algebra 1 -
**Bosnian**, Friday, February 21, 2014 at 3:17pm
SORRY:

A = 2 w ^ 2 + 4 w

OR

A = 2 ( w ^ 2 + 2 w )

OR

A = 2 w ( w + 2 )

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