-(6-c)+3(2c-7)=1
-(6-c)+3(2c-7)=1
-6 + c + 6c - 21 = 1
7c - 27 = 1
7c = 28
c = 4
please explain.
Combine like terms.
Add 27 to both sides.
Divide both sides by 7.
Please use the same name for your posts.
To solve the equation -(6-c) + 3(2c-7) = 1, follow these steps:
Step 1: Distribute the 3 to both terms inside the parentheses:
-(6-c) + 3(2c) - 3(7) = 1
Simplifying this gives:
-(6-c) + 6c - 21 = 1
Step 2: Remove the parentheses by applying the negative sign to both terms within the first parentheses:
-6 + c + 6c - 21 = 1
Combine the like terms:
7c - 27 = 1
Step 3: Isolate the term with the variable on one side by adding 27 to both sides of the equation:
7c - 27 + 27 = 1 + 27
Simplifying this gives:
7c = 28
Step 4: Solve for c by dividing both sides of the equation by 7:
7c/7 = 28/7
Simplifying this gives:
c = 4
Therefore, the value of c that satisfies the equation -(6-c) + 3(2c-7) = 1 is c = 4.