A woman wantes to drive 82 km in 2 h. If she average 38 km/h for the first 1.47 h, what average velocity must she maintain for the remaining time in km/h?
avgvelocity= distance/time
82/2= (38*1.47+speed*.53)/2hrs
solve for speed.
A car traveling at 26.8 m/s hits a stone wall . The driver, who is wearing a shoulder harness and seat belt, moves forward 0.99 m as the car stops. Assuming his acceleration is uniform, find his acceleration. in m/s2? (don't forget the (-) if negative)
To find the average velocity for the remaining time, we first need to determine the distance covered during the first 1.47 hours.
Distance = Speed * Time
Distance = 38 km/h * 1.47 hours
Now we can calculate this:
Distance = 55.86 km
Next, we need to determine the remaining distance to be covered:
Remaining distance = Total distance - Distance covered
Remaining distance = 82 km - 55.86 km
Now we can calculate this:
Remaining distance = 26.14 km
Finally, we can calculate the average velocity for the remaining time:
Average velocity = Remaining distance / Remaining time
We know the remaining time is 2 hours minus 1.47 hours, which is 0.53 hours.
Now we can calculate this:
Average velocity = 26.14 km / 0.53 hours
Therefore, the woman must maintain an average velocity of approximately 49.25 km/h for the remaining time to reach her destination.