A jet plane accelerates on a runway from rest at 4.03 m/s2. After 5 s, find its velocity in m/s?

v = a t = 20.15 m/s

To find the velocity of the jet plane after 5 seconds, you can use the equation of motion:

Final velocity (v) = Initial velocity (u) + Acceleration (a) × Time (t)

Given:
Initial velocity (u) = 0 m/s (because the jet plane starts from rest)
Acceleration (a) = 4.03 m/s^2
Time (t) = 5 s

Using the equation, we can plug in the values:

v = 0 + (4.03 × 5)
v = 0 + 20.15
v = 20.15 m/s

So, the velocity of the jet plane after 5 seconds is 20.15 m/s.