A jet plane accelerates on a runway from rest at 4.03 m/s2. After 5 s, find its velocity in m/s?
v = a t = 20.15 m/s
To find the velocity of the jet plane after 5 seconds, you can use the equation of motion:
Final velocity (v) = Initial velocity (u) + Acceleration (a) × Time (t)
Given:
Initial velocity (u) = 0 m/s (because the jet plane starts from rest)
Acceleration (a) = 4.03 m/s^2
Time (t) = 5 s
Using the equation, we can plug in the values:
v = 0 + (4.03 × 5)
v = 0 + 20.15
v = 20.15 m/s
So, the velocity of the jet plane after 5 seconds is 20.15 m/s.