Thursday

October 30, 2014

October 30, 2014

Posted by **Bruce** on Wednesday, February 19, 2014 at 1:30pm.

- Calc 2 -
**Damon**, Wednesday, February 19, 2014 at 1:52pmx^.5 * sin (1/x)

as 1/x ---> 0 , sin (1/x) = 1/x

x^.5 * x^-1 = x^-.5 = 1/sqrt x

which = 0 as x ---> infinity

- Calc 2 -
**Steve**, Wednesday, February 19, 2014 at 1:57pmor, by this time you have probably seen L'Hospital's Rule, so

limit √x sin(1/x)

if u = 1/x, then we have

limit sin(u)/√u

= limit cos(u)/(1/2√u)

= limit 2√u cos(u) as u->0

= 0

**Answer this Question**

**Related Questions**

calculus - Help - I have three problems that I am stuck on - 1. Lim x approaches...

Calc. Limits - Are these correct? lim x->0 (x)/(sqrt(x^2+4) - 2) I get 4/0...

calc - Are these correct? lim x->0 (x)/(sqrt(x^2+4) - 2) I get 4/0= +/- ...

Calc Please Help - Are these correct? lim x->0 (x)/(sqrt(x^2+4) - 2) I get 4/...

Calculus - Does the series (1+sin(n))/(10^n) from summation 0 to positive ...

Calc Help :((((( - lim x-> infinity (7x^(5/3)-2x^(1/3)+6)/(-2x^(8/5)-5x+...

Calculus - Find the following limit if it exists, or explain why it does not ...

calc bc (condensed - is the limit as x approaches 0 of sin3x over 3x equal to ...

Calculus - Show that limit as n approaches infinity of (1+x/n)^n=e^x for any x&...

calc - Use L’Hopital’s rule to find the limit of this sequence (n^100)/(e^n) ......