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October 25, 2014

October 25, 2014

Posted by **daniel** on Wednesday, February 19, 2014 at 11:20am.

- Statistics -
**PsyDAG**, Thursday, February 20, 2014 at 1:33pmIf you are comparing two means, you need to have the SEm, which requires knowledge of n. You do not supply that value.

Z = (mean1 - mean2)/standard error (SE) of difference between means

SEdiff = √(SEmean1^2 + SEmean2^2)

SEm = SD/√n

If only one SD is provided, you can use just that to determine SEdiff.

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score.

- Statistics -
**statstud**, Tuesday, February 25, 2014 at 5:35pm(29-25)/4= 4/4= 1

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