A ship is 24 miles east of port.how far. North must the ship sail to reach a point that is 25 miles from port?
a^2+b^2=c^2
a=24
b=25
c= squareroot(24^2+25^2)=34.6554469
what is 25^2=24^2 + d^2, solve for d.
idk
To find out how far north the ship must sail to reach a point that is 25 miles from port, we can use the Pythagorean theorem. The Pythagorean theorem states that in a right-angled triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.
In this case, the eastward distance of the ship from the port forms one side of a right-angled triangle, and the northward distance we want to find is another side. The hypotenuse is the distance between the ship and the point 25 miles from port.
Let's label the northward distance as 'x'. According to the Pythagorean theorem:
x^2 + 24^2 = 25^2
Simplifying the equation:
x^2 + 576 = 625
Subtracting 576 from both sides:
x^2 = 49
Taking the square root of both sides:
x = ±√49
Since distance cannot be negative, we take the positive square root:
x = 7
Therefore, the ship must sail 7 miles north to reach a point that is 25 miles from port.