If a spinner has 10 equal-sized sections, which of the following will be false?
P(1) = 10%
P(not 1) = 10%
P(2) = 10%
P(not odd) = 50%
obviously it is P(not 1) = 10% because that implies that 2, 3, 4, 5, 6, 7, 8, 9, and 10 have 10% chance against 1. so each number that is not 1 will have less than 1% of a chance to beat 1.
or just nine out of ten of your slots are not one so the chances of hitting any one of them is certainly not 0.1
To determine which of the statements is false, we can calculate the probabilities based on the given information. The spinner has 10 equal-sized sections, so each section has a probability of 1/10 or 10% of being selected.
Statement 1: P(1) = 10%
This statement is true because there is one section labeled 1 out of 10 sections, so the probability of landing on 1 is indeed 10%.
Statement 2: P(not 1) = 10%
This statement is also true because there are 9 sections that are not labeled 1. The probability of landing on any of those 9 sections is 9/10 or 90%. Therefore, the probability of not landing on 1 is 90%. Thus, this statement is false.
Statement 3: P(2) = 10%
Similar to statement 1, there is one section labeled 2 out of 10 sections. So, the probability of landing on 2 is indeed 10%. Therefore, this statement is true.
Statement 4: P(not odd) = 50%
An odd number is any number that is not divisible evenly by 2. Out of the 10 sections on the spinner, there are 5 that are odd (1, 3, 5, 7, and 9) and 5 that are even (2, 4, 6, 8, and 10). The probability of landing on an odd number is 5/10 or 50%. Therefore, this statement is true.
In summary, statement 2 (P(not 1) = 10%) is false.
I just broke it down for Jamar because this is a rather simple question, so I didn't know if he needed extra help on this or if he was just being lazy and not doing his homework.
same question as the last one really.
Come on guess and say why you guessed that.