Physics
posted by Sherri on .
An object initially at rest experiences an acceleration of 1.4m/s2 for 8.0s and then travels at that constant velocity for another 6.0s . What is the object’s average velocity over the 14s interval?

first stage
v = a t = 1.4 * 8 = 11.2 m/s
x = .5 a t^2 = .7 * 64 = 44.8 meters
stage 2
Vi = 11.2
Xi = 44.8
a = 0
x = 44.8 + 11.2*6 = 112
went 112 meters in 14 seconds
112/14 = 8 meters/second average