Saturday

February 28, 2015

February 28, 2015

Posted by **john** on Monday, February 17, 2014 at 11:29pm.

- math -
**Reiny**, Tuesday, February 18, 2014 at 12:07amI have a strong feeling you meant:

(1-tan^2 Ø)/(1 + tan^2Ø) + 2tan^2 Ø

= (1 - sin^2 Ø/cos^2 Ø)/sec^2 Ø + 2sin^2 Ø/cos^2 Ø

= (1 - sin^2 Ø/cos^2 Ø)(cos^2 Ø) + 2sin^2 Ø/cos^2 Ø

= cos^2 Ø - sin^2 Ø + 2sin^2 Ø/cos^2 Ø

this is in terms of sines and cosines

we could write it as

cos (2Ø) - 2sin^2 Ø/cos^2 Ø

anything beyond that would only make it more complicated.

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