Posted by john on .
1tan^2 theta/1+tan^2 theta + 2sin^2 theta need to simply to sin and cos

math 
Reiny,
I have a strong feeling you meant:
(1tan^2 Ø)/(1 + tan^2Ø) + 2tan^2 Ø
= (1  sin^2 Ø/cos^2 Ø)/sec^2 Ø + 2sin^2 Ø/cos^2 Ø
= (1  sin^2 Ø/cos^2 Ø)(cos^2 Ø) + 2sin^2 Ø/cos^2 Ø
= cos^2 Ø  sin^2 Ø + 2sin^2 Ø/cos^2 Ø
this is in terms of sines and cosines
we could write it as
cos (2Ø)  2sin^2 Ø/cos^2 Ø
anything beyond that would only make it more complicated.