A group of 52 people attendance ball game. There are three times as many children as adults in the group. Write a system of equations that you can use to solve this problem where a is the number amd C is the number of children in the group. How many children are in the group

c+a = 52

c = 3a

3a+a = 52
a = 13
so, c=39

In order to write a system of equations to solve this problem, let's assign variables to the unknowns in the problem. Let's say "a" represents the number of adults in the group, and "c" represents the number of children in the group.

We are given two pieces of information:
1. The total number of people in the group is 52.
2. There are three times as many children as adults in the group.

Based on this information, we can write the following equations:

Equation 1: a + c = 52 (since the total number of people in the group is 52)

Equation 2: c = 3a (since there are three times as many children as adults in the group)

Now, we have a system of equations:
a + c = 52
c = 3a

To find the number of children in the group, we can solve this system of equations. Substituting the value of c from Equation 2 into Equation 1, we get:

a + 3a = 52
4a = 52
a = 13

Now, substitute the value of a back into Equation 2:

c = 3(13)
c = 39

Therefore, there are 39 children in the group.