What is the density of a 33.13 g irregularly shaped object if the initial volume of water was 22.9 ml and the volume rose to 64.8 ml after the object was added?

volume = 64.8-22.9 = ? mL = ? cc.

Then density = mass/volume = ? g/cc or g/mL.

To find the density of the irregularly shaped object, you need to use the formula:

Density = Mass / Volume

In this case, the mass of the object is given as 33.13 g. To calculate the volume of the object, you need to determine the difference in volumes before and after the object was added to the water.

The initial volume of water was 22.9 ml, and after the object was added, the volume rose to 64.8 ml. To find the volume of the object, you subtract the initial volume from the final volume:

Volume of the object = Final volume - Initial volume
Volume of the object = 64.8 ml - 22.9 ml
Volume of the object = 41.9 ml

Now that you have the mass of the object (33.13 g) and the volume (41.9 ml), you can calculate the density using the formula:

Density = Mass / Volume
Density = 33.13 g / 41.9 ml

To get the answer, you can divide the mass by the volume:

Density ≈ 0.79 g/ml

Therefore, the density of the irregularly shaped object is approximately 0.79 g/ml.