A block with a mass of 1.0kg is lifted up slowly from ground (0m) to height of 0.51m.
block is slowly displaced horizontally by .10m.
find total work done to displace block vertically and horizontally.
Then find total work to lift block and move it horizontally.
NO WORK IS DONE TO MOVE HORizontaly !!!!!!
there is no horizontal forCE !!! Do not be fooled !!!
m g h = 1 * 9.81 * .51 = 5.00 Joules
To find the total work done to displace the block vertically and horizontally, we need to calculate the work done for each displacement separately and then sum them up.
1. Work done to displace the block vertically:
The vertical displacement of the block is given as 0.51m. We know that work done (W) is equal to the force (F) applied on an object multiplied by the distance (d) over which the force is applied, and in this case, it is the weight of the block that performs the work. The weight of an object is given by the equation W = mg, where m is the mass and g is the acceleration due to gravity (approximately 9.8 m/s²).
So, the work done vertically is equal to Wv = mg * d, where m = 1.0 kg and d = 0.51 m.
2. Work done to displace the block horizontally:
The horizontal displacement of the block is given as 0.10m. In this case, the work done is equal to the force applied horizontally multiplied by the distance. Since the block is displaced horizontally slowly, it is safe to assume that the force applied is equal to the force of friction (Ff) acting against the displacement.
The work done horizontally is equal to Wh = Ff * d, where d = 0.10 m.
Now, to find the total work to lift the block and move it horizontally, we need to calculate the sum of the vertical and horizontal work:
Total work = Wv + Wh
Plug in the respective values to find the total work done.