Posted by **Segun Akowonjo** on Friday, February 14, 2014 at 8:22pm.

A snowmobile is originally at the point with position vector 28.7 m at 95.0° counterclockwise from the x axis, moving with velocity 4.85 m/s at 40.0°. It moves with constant acceleration 1.94 m/s2 at 200°. After 5.00 s have elapsed, find the following:

(a)Its velocity vector

(b)Its position vector

- physics -
**Steve**, Friday, February 14, 2014 at 11:14pm
s0 = 28.7 @ 95.0° = -2.501,28.591

v0 = 4.85 @ 40.0° = 3.715,3.119

a = 1.94 @ 200° = -1.823,-0.664

Now, we just plug in our usual equations:

v = v0 + at

s = s0 + v0*t + 1/2 at^2

and then convert back to polar form as needed.

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