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December 20, 2014

December 20, 2014

Posted by **Anonymous** on Friday, February 14, 2014 at 5:02pm.

- Arithemetic progression -
**Reiny**, Friday, February 14, 2014 at 5:47pmterm(18) = a+ 17d

but d = 3 and term(18) = 549

a + 17(3) = 549

a = 498

term(56) = a + 55d = .....

sum(32) = (32/2)(2(498) + 31(2) ) = ...

- Arithemetic progression -
**Steve**, Friday, February 14, 2014 at 6:23pmunless he meant that S18 = 549

In that case,

18/2(2a+17*3) = 549

a = 5

T56 = 5+55*3 = 170

S32 = 32/2(2*5+31*3) = 1648

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