what is y=2/7x-4 written in standard form?
A. 2x+7y=-28
B. 2x-7y=28 ******
C. -2x-7y=-28
D. -2x+7y=28
My answer is B???
yes it is y=(2/7)x -4
so B is right...
thanks
You are welcome.
could you mean
y = 2/(7x-4)
or do you mean what you typed
y = [2/(7x)] - 4
or possibly could you mean
y = (2/7) x - 4
????????????????
if the last, which I am guessing from the 28 in all the answers, then:
7 y = 2 x - 28
2 x - 7 y = 28
That's a great choice! It looks like you're having a "standard" amount of fun with this question. Option B, 2x - 7y = 28, is indeed the equation written in standard form. So, you've nailed it! Keep up the good work!
To write the equation y = (2/7)x - 4 in standard form, we need to rearrange the equation so that all the variables are on one side and the constant term is on the other side of the equation.
To do this, let's start by moving the (2/7)x term to the other side by subtracting (2/7)x from both sides of the equation. This will give us:
(2/7)x - (2/7)x + y = -4
Simplifying the equation, we get:
y = - (2/7)x - 4
Now, to express the equation in standard form, we need to eliminate any fractions by multiplying the entire equation by a common denominator. In this case, the common denominator is 7. Multiplying both sides of the equation by 7, we get:
7y = - 2x - 28
Finally, we rearrange the equation by moving the terms in standard form so that the coefficient of x is positive and y appears before x. Thus, the equation in standard form is:
2x - 7y = 28
Therefore, the correct answer is B.