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March 31, 2015

March 31, 2015

Posted by **Miracle** on Friday, February 14, 2014 at 6:13am.

- Math.G.P -
**Reiny**, Friday, February 14, 2014 at 9:28amarithmetic mean of 1st and 3d

= (x-2 + x+6)/2

= (2x + 4)/2

= x+2

let the 2nd be y

then y/(x-2) = (x+6)/y

y^2 = (x-2)(x-6)

y = ± √((x-2)(x+6))

mean:2nd = 5:3

(x+2)/√((x-2)(x+6)) = 5/3

square both sides and expand

(x^2 + 4x + 4)/(x^2 + 4x - 12) = 25/9

25x^2 + 100x - 300 = 9x^2 + 36x + 36

16x^2 + 64x - 336 = 0

x^2 + 4x - 21 = 0

(x+7)(x-3) = 0

x = -7 or x = 3

check:

if x = -7,

the 3 terms are : -9, ±3, -1

(only the sequence -9, -3, -1 works)

if x = 3

the 3 terms are :1, ±3, 9

(only the sequence 1 , 3, 9 works)

so x = -7 or x = 3

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