Thursday

December 18, 2014

December 18, 2014

Posted by **malobisa** on Thursday, February 13, 2014 at 5:01am.

- area and perimeter -
**Steve**, Thursday, February 13, 2014 at 5:13amif the length is x and the width is y, then

2x+3y = 1200

a = xy = x(1200-2x)/3 = 400x - 2x^2/3

max area when x = 400*3/4 = 300

So, the field is 300 by 200

Note that as in all such problems, the fencing is divided equally among the lengths and widths.

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