Posted by **malobisa** on Thursday, February 13, 2014 at 5:01am.

a farmer wishes to build a fence around a rectangular field and divide it into two equal parts as well.the dividing fence must be parallel to one of the side of the field. you are asked to find dimension of the field of maximum area that you can fence and divide in two equal parts with a wire fence of 1200meter

- area and perimeter -
**Steve**, Thursday, February 13, 2014 at 5:13am
if the length is x and the width is y, then

2x+3y = 1200

a = xy = x(1200-2x)/3 = 400x - 2x^2/3

max area when x = 400*3/4 = 300

So, the field is 300 by 200

Note that as in all such problems, the fencing is divided equally among the lengths and widths.

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