Sunday

February 1, 2015

February 1, 2015

Posted by **malobisa** on Thursday, February 13, 2014 at 5:01am.

- area and perimeter -
**Steve**, Thursday, February 13, 2014 at 5:13amif the length is x and the width is y, then

2x+3y = 1200

a = xy = x(1200-2x)/3 = 400x - 2x^2/3

max area when x = 400*3/4 = 300

So, the field is 300 by 200

Note that as in all such problems, the fencing is divided equally among the lengths and widths.

**Answer this Question**

**Related Questions**

Math - A farmer wishes to put a fence around a rectangular field and then divide...

Math - a farmer wants to put a fence around a rectangular field and then divide ...

shortest fence - this is my last question from applications of derivatives! A ...

math - A rectangular field is to be enclosed by a fence. Two fences parallel to ...

Math - A rectangular study area is to be enclosed by a fence and divided into ...

Calculus 1 - A rectangular field is enclosed by a fence and seperated into two ...

calculus (optimization) - a rectangular study area is to be enclosed by a fence ...

calculas - A landowner wants to fence in a rectangular area of 60000 square ...

math - a farmer with 10,000 meters of fencing wants to enclose a rectangular ...

algebra2 - A farmer has 600 yards of fence. He will use some of the fence to ...