Posted by malobisa on .
a farmer wishes to build a fence around a rectangular field and divide it into two equal parts as well.the dividing fence must be parallel to one of the side of the field. you are asked to find dimension of the field of maximum area that you can fence and divide in two equal parts with a wire fence of 1200meter

area and perimeter 
Steve,
if the length is x and the width is y, then
2x+3y = 1200
a = xy = x(12002x)/3 = 400x  2x^2/3
max area when x = 400*3/4 = 300
So, the field is 300 by 200
Note that as in all such problems, the fencing is divided equally among the lengths and widths. 
area and perimeter 
Sumera,
30000