What is the peak wavelength and observed color of a 50,000 K star?
.58*10^-7 meters or 58 nm
http://hyperphysics.phy-astr.gsu.edu/hbase/quantum/wien3.html
plug in there
by the way I believe this is in the ultraviolet
To determine the peak wavelength and observed color of a 50,000 K star, we need to understand a fundamental principle known as Wien's Law. This law states that the peak wavelength (λ) of the radiation emitted by a black body (such as a star) is inversely proportional to its temperature (T).
The formula for Wien's Law is:
λ = (b / T)
Where:
λ = peak wavelength
b = Wien's constant (2.898 x 10^-3 m·K)
Let's calculate the peak wavelength for a 50,000 K star:
λ = (2.898 x 10^-3 m·K) / (50,000 K)
λ ≈ 0.05796 x 10^-6 m
We can convert the peak wavelength to nanometers (nm):
λ (in nm) = (0.05796 x 10^-6 m) * (1 nm / 10^-9 m)
λ ≈ 57.96 nm
Now, to determine the observed color of the star, we can refer to the electromagnetic spectrum and RGB color model. The human visual spectrum ranges approximately from 400 nm (violet) to 700 nm (red), with shorter wavelengths appearing bluish and longer wavelengths appearing reddish.
Since the peak wavelength of the 50,000 K star is around 57.96 nm, it lies in the ultraviolet spectrum as it is way below the visible range. Therefore, the observed color, if visible, would likely appear bluish-violet.
Please note that this is a general estimation based on the peak wavelength. The actual color observed from a star may be influenced by other factors such as its distance, atmospheric conditions, and the sensitivity of the observer's eye or equipment.