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February 1, 2015

February 1, 2015

Posted by **Steveo** on Tuesday, February 11, 2014 at 6:24pm.

a. How much is the car depreciating each year?

b. What was the purchase price of the car?

c. If the car continues this rate of depreciation, what will its value be at year 10?

- Algebra -
**Damon**, Tuesday, February 11, 2014 at 6:40pmvalue = v

purchase price = p

v = p - k t

24,000 = p - 3 k

19,000 = p - 5 k

------------------ subtract

5,000 = 2 k

k = 2,500 per year (part a)

24,000 = p - 7,500

p = 31,500

v(10) = 31,500 - 25,000 = 6,500

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