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December 22, 2014

December 22, 2014

Posted by **Steve** on Tuesday, February 11, 2014 at 5:38pm.

evaluate: f(sqrt2 + 3)

I have worked out this and am stuck:

(sqrt2+3)^2 - (sqrt2+3)

(sqrt2+3)*(sqrt2+3)- (sqrt2 +3)

(sqrt2)^2+ 3sqrt2 +3sqrt2+ 9- (sqrt2+3)

2+6sqrt2 +9-sqrt2-3

and am stuck or wrong here. Ans= SQRT2+6sqrt2 all under radical

- Precalculus -
**Damon**, Tuesday, February 11, 2014 at 6:34pm(sqrt2+3)^2 - (sqrt2+3)

let a = sqrt 2 so a^2 = 2

(a+3)^2 - (a+3)

a^2 + 6 a + 9 - a - 3

a^2 + 5 a + 6

2 + 5 sqrt 2 + 6

8 + 5 sqrt 2

- Precalculus -
**Steve**, Tuesday, February 11, 2014 at 7:36pmTHANKS!!

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