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November 28, 2014

November 28, 2014

Posted by **prawin** on Tuesday, February 11, 2014 at 6:17am.

n = 5 , p = 0.3 . Find the probabilities of

getting :

(i) Atleast 3 successes.

(ii) Atmost 3 successes.

n = 5 , p = 0.3

- binomial distribution -
**Damon**, Tuesday, February 11, 2014 at 7:13ambinomial coefficients for n = 5:

1 5 10 10 5 1

p = .3

1-p = .7

P(0) = .3^0 (.7)^5 = .168

p(1) = 5 (.3)^1(.7)^4 = .360

P(2) = 10 (.3)^2(.7)^3 = .309

P(3) = 10 (.3)^3(.7)^2 = .1323

P(4) = 5 (.3)^4(.7)^1 = .028

P(5) = 1 (.3)^5(.7)^0 = .002

first answer is P(3)+P(4)+P(5)

second answer is P(0)+P(1)+P(2)+P(3)

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