Chloroform CHCl is an important solvent. It is produced by a reaction between methane and chlorine. How many g CH4 are needed to produce 50.0g CH4 +Cl3+ CH_4 + 3Cl_2 ->CHCl_3 + 3HCl}

I'm assuming the question is "How many g CH4 are required to produce 50 g CHCl3?"

I think the equation you wrote is screwed up (or that CH4+Cl3 may be a typo); anyway, here are the steps.
1. Write and balance the equation.
2. Convert 50 chloroform to mols. mols = grams/molar mass
3. Using the coefficients in the balanced equation, convert mols CHCl3 to mols CH4.
4. Then convert mols CH4 to g. g = mols x molar mass.

To determine how many grams of CH4 are needed to produce 50.0g of CHCl3, we need to use the balanced equation for the reaction:

CH4 + 3Cl2 -> CHCl3 + 3HCl

According to the equation, it takes 1 mole of CH4 to produce 1 mole of CHCl3. We can use the molar mass of CH4 to convert grams of CHCl3 into moles, and then use the molar mass of CH4 to convert back to grams.

1. Calculate the molar mass of CH4:
C (carbon) = 12.01 g/mol
H (hydrogen) = 1.01 g/mol
Molar mass of CH4 = 12.01 + 4 * 1.01 = 16.05 g/mol

2. Calculate the number of moles of CHCl3:
Moles of CHCl3 = Mass of CHCl3 / Molar mass of CHCl3
Moles of CHCl3 = 50.0 g / 119.38 g/mol (molar mass of CHCl3)

3. Use the balanced equation to find the moles of CH4:
Since the equation is balanced in a 1:1 ratio, the moles of CH4 will be the same as the moles of CHCl3.

4. Calculate the mass of CH4:
Mass of CH4 = Moles of CH4 * Molar mass of CH4

Therefore, the mass of CH4 needed to produce 50.0g of CHCl3 can be determined using the steps above.