Monday

September 1, 2014

September 1, 2014

Posted by **christina** on Monday, February 10, 2014 at 10:39pm.

tinypic .cm /r / nfr48k/ 8

The correct answer is .1443 but I want to know how they got that. Thanks.

- Physics -
**Steve**, Tuesday, February 11, 2014 at 6:06amThe equivalent resistance from R2 and R3 is

1/R = 1/38 + 1/18

R = 12.214

So, we now have a total R of 16+12.214 = 28.214 ohms

That means our current through R1 and the R2R3 network is 6/28.214 = .212 amps

Now, divide that current between R2 and R3 and

Ix = .212(38/56) = .144

or so. Check my math and adjust sig figs.

**Answer this Question**

**Related Questions**

physics - Resistors R1, R2, and R3 have resistances of 15.0 Ohms, 9.0 Ohms and 8...

physics - so i have a circuit (series) where the the emf=12 V and R1=2 ohms and ...

circuits - so i have a circuit (series) where the the emf=12 V and R1=2 ohms and...

algebra - express R as rational expression 1/R=1/R2+1/R2+1/R3 R FOR R1=5 OHMS R ...

Physics - A battery with voltage drop of 120V is connected in a ciruit ...

physics-series and parellel circuits - I'll try to explain the schmatic drawing...

PHY [non-calc] - Resistors R1= 10ohms, R2= 40 ohms and R3= 70 ohms are connected...

Physics-Please help - R1= 10 ohm R2= 20 ohm R3= 50 ohm R4= ??? R1, R2, R3 and R4...

Physics - Consider the LR circuit. We have R1=9 Ohms, R2=5 Ohms, R3=19 Ohms, V=2...

Physics - A battery with voltage drop of 120V is connected in a ciruit ...