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February 1, 2015

February 1, 2015

Posted by **maria** on Monday, February 10, 2014 at 9:45pm.

travels 55.0(cm), and during the following two seconds, another 77.0(cm)

(a) Calculate the vehicle’s initial velocity and its acceleration.

(b) What distance will it travel the next 4.0(s)?

- physics -
**Damon**, Monday, February 10, 2014 at 10:19pm.55 = Vi(2) + (1/2) a 2^2

0.55 = 2 Vi + 2 a

total distance after 4 seconds = .55+.77

= 1.32 m

1.32 = 4 Vi + (1/2) a (4^2)

1.32 = 4 Vi + 8 a

--------------------

so solve these two equations for Vi and a:

1.32 = 4 Vi + 8 a

0.55 = 2 Vi + 2 a

- physics -
**maria**, Monday, February 10, 2014 at 10:40pmthank you so much Damon!

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