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Posted by on Monday, February 10, 2014 at 9:45pm.

A remote-control vehicle moves forward with constant acceleration. During the first two seconds, it
travels 55.0(cm), and during the following two seconds, another 77.0(cm)
(a) Calculate the vehicle’s initial velocity and its acceleration.
(b) What distance will it travel the next 4.0(s)?

  • physics - , Monday, February 10, 2014 at 10:19pm

    .55 = Vi(2) + (1/2) a 2^2

    0.55 = 2 Vi + 2 a

    total distance after 4 seconds = .55+.77
    = 1.32 m

    1.32 = 4 Vi + (1/2) a (4^2)
    1.32 = 4 Vi + 8 a
    --------------------
    so solve these two equations for Vi and a:
    1.32 = 4 Vi + 8 a
    0.55 = 2 Vi + 2 a

  • physics - , Monday, February 10, 2014 at 10:40pm

    thank you so much Damon!

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