Suppose that the average weight of students in a statistics class is 75.5 kilograms with a standard deviation of 10.3 kilograms.

A. 45% of the student weights are above ____ kilograms?

Z=.3264=x-75.5/10.3 Now what? I am lost! Please help me!
Thanks!

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability (.45) and its Z score. Insert the Z value in your equation and solve for x.