Wednesday

January 28, 2015

January 28, 2015

Posted by **Mary Anne** on Saturday, February 8, 2014 at 6:08pm.

- Southern Union -
**Damon**, Saturday, February 8, 2014 at 6:36pmHow fast is it going when it leaves the roof?

v = a T

d = .5 a t^2

64 = .5 * 3.35 * t^2

so t = 6.18 seconds on roof

v = 3.35 * 6.18 = 20.7 m/s leaving roof

Vertical velocity leaving roof = -20.7 sin 20 deg = -7.08 m/s

horizontal velocity roof to ground = 20.7 cos 20 = 19.5 m/s

do vertical problem first

Vi = -20.7

a = -9.8 so a/2 = -4.9

Hi = 33.5

0 = 33.5 - 20.7 t - 4.9 t^2

so

t^2 + 4.22 t - 6.84 = 0

t = [ -4.22 +/- 6.72 ]/ 2

= 1.25 seconds

distance horizontal = 19.5 t = 19.5*1.25 = 24.4 metars

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