Suppose a Stat 1450 web class has 15 males (8 are also students at OSU) and 12 females (7 are also students at OSU). What is the probability that a randomly selected student is either female, or also a student at OSU? Submit answer in decimal form and round to the nearest thousandths place.

what does "or also" mean?

I have the same question but perhaps I I list the four categories that the 27 students fit into you can figure it out yourself:

a) 7 males (not student)

b) 8 male students

c) 7 female students

d) 5 females (not student)

so males not student = 7/27
male students = 8/27
female students = 7/27
females not student = 5/27

So if you criterion is that any student counts plus any female student or not then it is

(8 + 7 + 5)/27

To find the probability that a randomly selected student is either female or also a student at OSU, we need to calculate the number of students who fit either of these criteria and divide it by the total number of students.

Let's start by finding the number of females in the class who are also students at OSU. We are given that there are 12 females in total, and 7 of them are students at OSU. Therefore, the number of females who are also students at OSU is 7.

Next, let's calculate the number of males in the class who are also students at OSU. We are given that there are 15 males in total, and 8 of them are students at OSU. Therefore, the number of males who are also students at OSU is 8.

Now, let's calculate the total number of students who fit either of the criteria (female or also a student at OSU). To do this, we add the number of females who are also students at OSU (7) to the number of males who are also students at OSU (8). This gives us a total of 15 students who fit either of the criteria.

Finally, we divide the total number of students who fit either of the criteria (15) by the total number of students in the class (27) to find the probability. Therefore, the probability that a randomly selected student is either female or also a student at OSU is 15/27 = 0.556 (rounded to the nearest thousandths place).

So the probability is approximately 0.556.