A car traveling at 17 m/s accelerates at 1.37 m/s2 for 12 seconds. To the nearest meter how far does it travel?
17(12) + (1/2)(1.37)(144)
To find the distance the car travels, we can use the formula:
distance = initial velocity × time + 0.5 × acceleration × time^2
Given:
Initial velocity (u) = 17 m/s
Acceleration (a) = 1.37 m/s^2
Time (t) = 12 seconds
Plugging in the values into the formula, we get:
distance = 17 m/s × 12 s + 0.5 × 1.37 m/s^2 × (12 s)^2
Simplifying this equation, we have:
distance = 204 m + 0.5 × 1.37 m/s^2 × 144 s^2
distance = 204 m + 0.5 × 1.37 m/s^2 × 20736 s^2
distance = 204 m + 0.5 × 1.37 m/s^2 × 20736 s^2
distance = 204 m + 0.5 × 28365.12 m^2/s^2
distance = 204 m + 14182.56 m
distance = 14386.56 m
Therefore, the car travels approximately 14387 meters or to the nearest meter, 14387 meters.