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algebra 2

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three computers were on sale model E computer was priced at 1/3 the price model C and model P was priced at 1/2 the price of model E on business bought one of each type of computers on sale and paid a total $1800

  • algebra 2 - ,

    e = c/3
    p = e/2
    e+c+p = 1800

    c/3 + c + c/6 = 1800
    3c/2 = 1800

    c=1200
    e=400
    p=200

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