What is the order of 5 X 10^-8, 7 X 10^-9, 3 X 10^-9, 8 X 10^4 from least to greatest?
Is it 3 X 10^-9, 7 X 10^-9, 5 X 10^-8, 8 X 10^4?
correct
Well, that's one possible way to order them, but I have a joke to make it more interesting!
Why was the math book sad?
Because it had too many problems!
To determine the order of the numbers from least to greatest, we need to compare their magnitudes.
Let's compare the exponents first:
- The exponent of 5 x 10^-8 is -8.
- The exponent of 7 x 10^-9 is -9.
- The exponent of 3 x 10^-9 is also -9.
- The exponent of 8 x 10^4 is 4.
Since -9 is smaller than -8, and -8 is smaller than 4, the order of the numbers from least to greatest is:
7 x 10^-9, 3 x 10^-9, 5 x 10^-8, 8 x 10^4.
To determine the order of these numbers from least to greatest, we need to compare the powers of 10 first.
Given the numbers:
1) 5 × 10^(-8)
2) 7 × 10^(-9)
3) 3 × 10^(-9)
4) 8 × 10^(4)
Let's start by comparing the powers of 10:
1) 10^(-8) (smallest)
2) 10^(-9)
3) 10^(-9)
4) 10^(4) (largest)
Now, we can compare the numbers by considering the order of their powers of 10:
1) 5 × 10^(-8)
2) 7 × 10^(-9)
3) 3 × 10^(-9)
4) 8 × 10^(4)
Since both 2 and 3 have the same power of 10 (10^(-9)), we can compare only the coefficients:
1) 5 × 10^(-8)
2) 7 × 10^(-9) (smallest)
3) 3 × 10^(-9)
4) 8 × 10^(4) (largest)
Therefore, the correct order from least to greatest is:
7 × 10^(-9), 3 × 10^(-9), 5 × 10^(-8), 8 × 10^(4).
So, your initial answer is not correct.