Calculate the value of Qc for the reaction above if 2.30 moles of NO2, 1.50 moles of NO, and 1.20 moles of O2 are placed in a 3.50 liter container at 30°C. Kc = 0.440 at this temperature.
Am I missing something? What do you mean Qc?
I assume Kc is the equilibrium constant.
Qc is the reaction quotient.
And also,
how would i solve this:
Calculate the equilibrium concentration of each compound if 0.310 moles of H2 and 0.310 moles of I2 are placed in a 4.30 liter container at 520°C. Kc = 0.190 for the reaction at this temperature.
To calculate the value of Qc, we need to write the balanced equation for the reaction and then use the given moles and the volume to calculate the molar concentration of each species.
The balanced equation for the reaction is:
2 NO2 (g) + O2 (g) ⇌ 2 NO (g)
Now, let's calculate the molar concentration (C) for each species using the given moles and the volume:
For NO2:
C(NO2) = moles(NO2) / volume = 2.30 moles / 3.50 L = 0.657 M
For NO:
C(NO) = moles(NO) / volume = 1.50 moles / 3.50 L = 0.429 M
For O2:
C(O2) = moles(O2) / volume = 1.20 moles / 3.50 L = 0.343 M
Now, let's calculate Qc by substituting the molar concentrations into the equation:
Qc = (C(NO))^2 * C(O2) / (C(NO2))^2
Qc = (0.429 M)^2 * 0.343 M / (0.657 M)^2
Qc = 0.185
So, the value of Qc for the given reaction is 0.185.