The temperature of 550. g of water is increased from 16.0 degrees Celsius to 28.2 degrees Celsius by burning fuel.

How many joules of energy is needed to increase the temperature of the water to 28.2 degrees?

q = mass H2O x specific heat H2O x (Tfinal-Tinitial)

To calculate the amount of energy required to increase the temperature of the water, we can use the equation:

Q = mcΔT

where:
Q represents the amount of energy (in joules)
m is the mass of the substance (in grams)
c is the specific heat capacity of the substance (in joules per gram per degree Celsius)
ΔT is the change in temperature (in degrees Celsius)

In this case, the mass of water (m) is given as 550. g, the specific heat capacity of water (c) is approximately 4.18 J/g°C, and the change in temperature (ΔT) is 28.2 - 16.0 = 12.2 degrees Celsius.

Now we can substitute the given values into the equation:

Q = (550. g) * (4.18 J/g°C) * (12.2°C)

By performing the calculation, we get:

Q = 29,653.6 joules

Therefore, approximately 29,653.6 joules of energy are required to increase the temperature of 550. g of water from 16.0 degrees Celsius to 28.2 degrees Celsius.