An object at rest accelerates through a distance of 1.5 m at which point the instantaneous velocity of the object is 3.5m/s. Determine:

a. The average acceleration of the object

b. The time it took the object to travel 1.5m

c. The average velocity of the object during this period of motion

I saw this question was posted below, but not answered yet. I was also curious on how to do it. Thanks for the help!

a = change in velocity /change in time

= 3.5/t

what is t?
average speed is (3.5 + 0)/2 = 1.75 (that is part c)
1.75 t = 1.5 meters
t = .857 second (that is part b)

so
a = 3.5 / .857 = 4.08 m/s^2 ( part a)

when acceleration is constant, average speed during acceleration is (initial speed + end speed) /2
which saves a lot of computation

vf^2=2ad solve for a.

b. vf=at solve for t

c. avg velocity= distance/time

You guys are the best ....thank you

You are welcome :)

To solve this problem, we can use the equations of motion from classical mechanics. Let's break it down step by step:

a. The average acceleration of an object is given by the formula:

average acceleration = (change in velocity) / (time taken)

In this case, we are given the initial velocity (0 m/s) and the final velocity (3.5 m/s). Since the object is at rest initially, the change in velocity is simply the final velocity. We need to calculate the time taken.

To find the time taken, we can use the following equation:

final velocity = initial velocity + (acceleration * time taken)

Since the initial velocity is 0 m/s and the final velocity is 3.5 m/s, we can rearrange the equation to solve for the time taken:

time taken = (final velocity - initial velocity) / acceleration

Since we have the final velocity and the acceleration, we can substitute those values into the equation to find the time taken.

b. The time it took the object to travel 1.5 m can be calculated using the equation of motion:

distance = initial velocity * time taken + (1/2) * acceleration * (time taken)^2

Since the initial velocity is 0 m/s, we can simplify the equation to:

distance = (1/2) * acceleration * (time taken)^2

We can rearrange this equation to solve for the time taken:

time taken = square root of ((2 * distance) / acceleration)

Substitute the given values of distance (1.5 m) and acceleration into this equation to find the time taken.

c. The average velocity of the object during this period of motion can be calculated using the formula:

average velocity = (initial velocity + final velocity) / 2

Since the initial velocity is 0 m/s and the final velocity is 3.5 m/s, we can substitute those values into the equation to find the average velocity.

By plugging in the appropriate values and solving these equations, you should be able to find the answers to parts a, b, and c of the given problem.