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March 3, 2015

March 3, 2015

Posted by **christina** on Monday, February 3, 2014 at 1:06am.

length = 10.27 cm; width = 4.92 cm; height = 1.53 cm

Assuming that each of these measurements is accurate to the nearest 0.01 cm, find the volume of the block and the fractional error on its volume due to measurement errors.

I keep getting .007 cm^3 what am I doing wrong?

- science -
**Henry**, Tuesday, February 4, 2014 at 8:40pmL min. = 10.26 cm

W min. = 4.91 cm

H min. = 1.52 cm

V nom. = 10.27 * 4.92 * 1.53=77.308 cm^3

V min. = 10.26 * 4.91 * 1.52=76.728cm^3

Error = 77.308 - 76.728 = 0.5796 cm^3

NOTE: The fractional error has no units;

they cancel.

Fractional Error = 0.58cm^3/77.308cm^3 =

0.0075

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