You measure the dimensions of a rectangular block of aluminum to determine its volume. It has the following dimensions.
length = 10.27 cm; width = 4.92 cm; height = 1.53 cm
Assuming that each of these measurements is accurate to the nearest 0.01 cm, find the volume of the block and the fractional error on its volume due to measurement errors.
I keep getting .007 cm^3 what am I doing wrong?
science - Henry, Tuesday, February 4, 2014 at 8:40pm
L min. = 10.26 cm
W min. = 4.91 cm
H min. = 1.52 cm
V nom. = 10.27 * 4.92 * 1.53=77.308 cm^3
V min. = 10.26 * 4.91 * 1.52=76.728cm^3
Error = 77.308 - 76.728 = 0.5796 cm^3
NOTE: The fractional error has no units;
Fractional Error = 0.58cm^3/77.308cm^3 =